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x^2-1.3x=0
a = 1; b = -1.3; c = 0;
Δ = b2-4ac
Δ = -1.32-4·1·0
Δ = 1.69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.3)-\sqrt{1.69}}{2*1}=\frac{1.3-\sqrt{1.69}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.3)+\sqrt{1.69}}{2*1}=\frac{1.3+\sqrt{1.69}}{2} $
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